Calculate the normality of H2SO4 solution if 45 ml of this solution neutralized with 60 ml of 0.52 N NAOH?

We know how many equivalents were used by multiplying volume of NaOH x Normality, so we get 0.52 x 0.060(L) = 0.0312 eq . We can then easily calculate the normality of the H2SO4 solution by dividing by the volume of H2SO4, so N=(0.0312) / (0.045 L) = 0.69 N.